Question

A volleyball is spiked so that its incoming velocity of +2.06 m/s is changed to an outgoing velocity of -19.2 m/s. The mass of the volleyball is 0.350 kg. What is the magnitude of the impulse that the player applies to the ball? Number Units

Answer 1

J = 8.78 kgm/s

Step-by-step explanation:

given mass of volleyball = 0.350 kg

incoming velocity = +2.06 m/s =
`v_(1)`

outgoing velocity =-19.2 m/s =
`v_(2)`

we know impulse is change in momentum

so impulse = J

`J =mv_(1) -( m(-v_(2)))\\J = m(v_(1)+v_(2))\\J = 0.350( 2.06 + 19.2)\\ J = 0.350 * 19.2\\ J = 8.78 kg m/s`