Answer:
The recoil speed of Astronaut A is 0.26 m/s.
Step-by-step explanation:
Given that,
Mass of astronaut A,
![m_A=110\ kg](https://img.qammunity.org/2021/formulas/physics/college/eeiui32grn19pbig4m80pkvijq4o2861wm.png)
Mass of astronaut B,
![m_B=74\ kg](https://img.qammunity.org/2021/formulas/physics/college/lons5cybcxcfzq86gyjuukdmlunen14zw7.png)
Astronaut A pushes B away, with B attaining a final speed of 0.4,
![v_B=0.4\ m/s](https://img.qammunity.org/2021/formulas/physics/college/1otukm3djb6pm0ici6om54ecjhorej68l8.png)
We need to find the recoil speed of astronaut A. The momentum remains conserved here. Using the law of conservation of linear momentum as :
![m_Av_A=m_Bv_B\\\\v_A=(m_Bv_B)/(m_A)\\\\v_A=(74* 0.4)/(110)\\\\v_A=0.26\ m/s](https://img.qammunity.org/2021/formulas/physics/college/oqryizqekwx31rk8q8vais110a6vg2uzat.png)
So, the recoil speed of Astronaut A is 0.26 m/s.