Question

A certain brand of hot-dog cooker works by applying a potential difference of 120 V across opposite ends of a hot dog and allowing it to cook by means of the thermal energy produced. The current is 10.0 A, and the energy required to cook one hot dog is 60.0 kJ. If the rate at which energy is supplied is unchanged, how long will it take to cook three hot dogs simultaneously

Answer 1

To cook three hot dogs simultaneously, it would take 150 seconds.

Step-by-step explanation:

To calculate the time required to cook three hot dogs simultaneously, we need to calculate the total energy required to cook three hot dogs and then divide it by the rate at which energy is supplied. Since the energy required to cook one hot dog is 60.0 kJ, the energy required to cook three hot dogs would be 60.0 kJ * 3 = 180.0 kJ.

The rate at which energy is supplied is 10.0 A * 120 V = 1200 W = 1.2 kW = 1.2 kJ/s.

So, the time required to cook three hot dogs simultaneously would be 180.0 kJ / 1.2 kJ/s = 150 seconds.

Answer 2

The time it will take to cook three hot dogs simultaneously is 2.5 minutes

Step-by-step explanation:

Here we have, the Energy of electric heating given by Joule heating that is;

P = IV = 120×10 = 1200 J/s = 1.2 kJ/s

Since the energy required to cook one hotdog = 60.0 kJ we have

Energy required to cook three hot dogs = 3 × 60.0 kJ = 180.0 kJ

Therefore, the time required to cook the three hot dogs is

(180.0 kJ)/(1.2 kJ/s) = 150 s

The time it takes to cook three hot dogs simultaneously is

150 seconds or 150/60 minutes which is 2 minutes 30 seconds or 2.5 minutes