Question

Which contains more molecules of water. 5 liters of ice at 0 degrees Celsius or 5 liters of water at 0 degrees Celsius?

Answer 1

5 grams of water will have more water molecules since ice had 1.67 x
`10^(23)` molecules and 5 gm ice had 1.53 x 10
`10^(23)` molecules of water.

Step-by-step explanation:

5 liters of water at 0 degrees or 273.15 K will have, Formula used is:

number of water molecules =
`(mass)/(atomic mass of 1 mole)` x Avagadro number

Avagadro number = 6.022 X 10 ^23 molecules or atoms in 1 mole

atomic mass of 1 mole water = 18.01 grams/mole

putting the value in the equation:

number of molecules =
`(5)/(18.01)` x 6.022 x 10^23

number of molecule of water in water = 1.67 X
`10^(23)` molecules.

5 gm cm^3 of ice will have

The density of ice = 0.917 gm/cm^3

volume = density x mass

number of moles of water =
`(density x mass)/(atomic mass of water)` x Avagadro number

putting the values,

number of moles in ice =
`(0.917 X 5)/(18.01)` X 6.022 X 10^23

= 1.53 X
`10^(23)` molecules of water