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4 votes
How to do 7z2 5z4 d3 d8

User Jyoti
by
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1 Answer

5 votes

Answer:


35{z}^(6) \cdot \: {d}^(11)

Explanation:

Let us assume , we want to find the product of


7 {z}^(2) \cdot \: 5 {z}^(4) \cdot \: {d}^(3) \cdot \: {d}^(8)

We rewrite as:


7 * 5{z}^(2) \cdot \: {z}^(4) \cdot \: {d}^(3) \cdot \: {d}^(8)

We multiply coefficients and apply the product rule of exponents.

According to the product rule, when the base is the same for a product, we write one base and add the exponents.


35{z}^(2 + 4) \cdot \: {d}^(3 + 8)

We simplify the exponents to get;


35{z}^(6) \cdot \: {d}^(11)

User HjalmarCarlson
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