Question

In ΔNOP, the measure of ∠P=90°, the measure of ∠O=17°, and OP = 8.6 feet. Find the length of PN to the nearest tenth of a foot.

Answer 1

The length of PN is 2.63 feet

Step-by-step explanation:

Given:

∠P=90°,

∠O=17°,

OP = 8.6 feet

PN = ?

The given triangle is a right angle triangle as one angle is 90°

We know:

`tan \alpha = (perpendicular)/(base)`

`tan(17^o) = (PN)/(OP) \\\\0.3057 = (PN)/(8.6) \\\\PN = 0.3057 X 8.6 feet\\\\PN = 2.63 feet`

Therefore, the length of PN is 2.63 feet