Answer: -8.4 x 10^6N
Step-by-step explanation:
Given that,
negative charge (q1) = -2.0C
positive charge (q2) = 3.0C
Distance between charges (r) = 80 m
force between the two charges (F) = ?
Apply the formula for
F= (kq1q2) / r^2
Recall that k is Coulomb's constant with a value of 9 × 10^9 Nm2C−2
Then,
F = (9 × 10^9 Nm2C−2 x -2.0C x 3.0C) / (80m)^2
F = (-5.4 x 10^10) / (6400m)^2
F = -8437500N
Place result in standard form
F = -8.4 x 10^6N
Thus, the force between the two charges is -8.4 x 10^6 newton