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Use the ratio or root test to check if the series converges


\sum_(n=2)^(\infty) (n)/((ln(n))^n)

1 Answer

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Answer:

Converges

Explanation:

n = k+1

(k+1) ÷ [ln(k+1)]^(k+1)

n = k

k ÷ [ln(k)]^k

{(k+1) ÷ [ln(k+1)]^(k+1)} ÷ {k ÷ [ln(k)]^k}

= {(k+1)/k} × {[ln(k)]^k}/{[ln(k+1)]^(k+1)}

{[ln(k)]^k}/{[ln(k+1)]^(k+1)} is decreasing at a much faster rate than the rate of increase of {(k+1)/k}.

Therefore the product is less than 1.

Hence it converges

User Vallllll
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