Question

The volume of a gas is 59.5 liters at 121 kPa. what will be the volume if the pressure is reduced to 108 kPa, assuming temperature remains the same ?

Answer 1

The volume of the gas V2 is 66.67 L

Step-by-step explanation:

Given data

V1= 59.5 L

V2=?

T1= 121K Pa

T2= 108 K Pa

We have the formula,

V1/T1 =V2/T2

Rewrite the formula as,

V2= VI T1/T2

V2= 59.5 L * 121 K Pa/108 K Pa

V2=7199.5 L K Pa/ 108 K Pa

V2=66.67 L

The volume of the gas V2 is 66.67 L