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If r= - square root2 and a^5= 32square root2, what is the first term of the sequence?

1 Answer

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Answer:

8√2

Explanation:

r=-√2

a5=32√2

an=a1(r)^{n-1}

32√2=a1(-√2)^{5-1}=a1×(-√2)^4=a1×4


a1=(32√(2))/(4)=8√(2)

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