Question

Select the correct answer.

What is the solution to this system of equations?
x - 2y= 15
2x+4y= -18
A.
x= 1, y= -6
B.
C.
x= 1, y=-7
x= 3, y= -6
D.
x= 3, y=-7

Answer 1

x= 3 and y =-6

Explanation:

I used elimination to solve it.

multiply the first equation by 2 so you can cancel out he y values

2 (x-2y=15)

2x- 4y = 30

2x +4y = -18 you can now eliminate -4y+4y because it makes

add the x's together 2x + 2x and do 30-18

4x=12 divide by 4

x =3

now that you know the value of x you use it to solve one of the original equations

3 -2y =15 subtract 3 from both sides

-2y = 15-3

-2y = 12 divide by -2

y = -6

Answer 2

Answer is option c

Explanation:

`given \: equations \: are \\ x - 2y = 15 \: \: and \: 2x + 4y = - 18 \\ divide \: by \: 2 \: in \: second \: equation \\ x + 2y = - 9 \: \: (equation \: 3) \\ adding \: 1and \: 3 \: we \: get \\ 2x = 6 \\ x = 3 \\ substitute \: x = 3 \: in \: equation \: 3 \\ 3 + 2y = - 9 \\ 2y = - 9 - 3 \\ 2y = - 12 \\ y = - 6`

x=3 and y=-6

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