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Vertical asymptote of the function f(x)= x+2/x^2-3x-4

User Skydroid
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1 Answer

4 votes

Answer:

x = 4, -1

Explanation:

You first have to find the value of x where the denominator is equal to 0 because this is where the function will become undefined:


x^(2) - 3x - 4 = 0

Now, to factor by grouping, find 2 numbers which add to -3 and multiply to -4:

1 and -4

Then, factor by grouping:

(x + 1)(x - 4) = 0

Next, solve for the values of x:

(x + 1) = 0

x = -1

(x - 4) = 0

x = 4

Finally, this means that the function has a vertical asymptote of x = 4 and x = -1

User Nitin Srivastava
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5.6k points