Question

In a population of gophers, the frequency of the W allele is 0.60 and the frequency of the w allele is 0.40. If the population is in H/W equilibrium, what is the expected frequency of heterozygotes? a. 0.16 b. 0.20 c. 0.32 d. 0.48 e. 0.80

Answer 1

d

Step-by-step explanation:

Hardy Weinberg equilibrium equation is represented below

p² + 2pq + q²

p = 0.6 and q = 0.4

with p² representing homozygous dominant frequency and q² representing homozygous recessive frequency

the expected frequency is of heterozygotes = 2pq = 2 × 0.60 × 0.40 = 0.48