Question

thermal energy is being added to steam at 475.8 kPa and 75% quality. determine the amount of thermal energy to be added to create saturated steam. what is the temperature of the 75% quality steam.?

Answer 1

`q_(in) = 528.6\,(kJ)/(kg)`

Step-by-step explanation:

Let assume that heating process occurs at constant pressure, the phenomenon is modelled by the use of the First Law of Thermodynamics:

`q_(in) = h_(g) - h_(mix)`

The specific enthalpies are:

Liquid-Vapor Mixture:

`h_(mix) = 2217.2\,(kJ)/(kg)`

Saturated Vapor:

`h_(g) = 2745.8\,(kJ)/(kg)`

The thermal energy per unit mass required to heat the steam is:

`q_(in) = 2745.8\,(kJ)/(kg) - 2217.2\,(kJ)/(kg)`

`q_(in) = 528.6\,(kJ)/(kg)`