Question

Given 7.65 mol AgNO3, determine the number of formula units.

Answer 1

The number of formula units of silver nitrate is
`4.61* 10^(24)`.

Step-by-step explanation:

Moles of silver nitrate = n = 7.65 mol

1 mole =
`N_A=6.022* 10^(23)` atoms/ molecules/ ions

Let the number of formula units of silver nitrate be N.

`N=n* N_A`

`N=7.65 mol* 6.022* 10^(23)=4.61* 10^(24)`

The number of formula units of silver nitrate is
`4.61* 10^(24)`.