Question

A professor stevens wants to mix a solution (a mixture of substance and water) containing 13% acid with one containing 18% acid to obtain a 50 millimeter solution containing 16% acid. How many milliliters of the 13% solution should the professor use?

Answer 1

20 ml 13% solution should the professor use

Step-by-step explanation:

Let

the volume of the 13% solution should the professor use = a

So, according to question

13% x a + 18% x (50-a) = 50 x 16%

⇒ 0.13 a + 0.18 x 50 - 0.18 a = 50 x 0.16

⇒ - 0.05 a = 8 - 9

⇒
`a=(-1)/(-0.05) = 20ml`

So, 20 milliliters of the 13% solution should be the professor used.

& (50 - 20) = 30 ml of the 18 % solution would be use.