Question

What is the binding energy of an electron that requires a photon with a maximum wavelength of 430 nm to eject it? If a photon with a frequency of 8.21 x 1015 Hz is used, what is the kinetic energy of the electron?

Answer 1

The kinetic energy of the electron is
`4.98* 10^(-18)\ J`.

Step-by-step explanation:

Given that,

The maximum wavelength of a photon is 430 nm.

The frequency of a photon is
`8.21* 10^(15)\ Hz`

It is a case of photoelectric effect. The relation between the kinetic energy and the the work function as :

`K=hf-W_o\\\\K=hf-h(c)/(\lambda)\\\\K=h(f-(c)/(\lambda))\\\\K=6.63* 10^(-34)* (8.21* 10^(15)-(3* 10^8)/(430* 10^(-9)))\\\\K=4.98* 10^(-18)\ J`

So, the kinetic energy of the electron is
`4.98* 10^(-18)\ J`.