Question

The gas in a balloon occupies 3.50 L at 300.0 K. At what temperature will the balloon expand to 8.50L?

Answer 1

To find at what temperature a balloon will expand to 8.50L from an initial volume of 3.50L at 300.0K, we apply Charles's law, leading to a final temperature of 730K.

Step-by-step explanation:

When considering how the volume of a gas changes with temperature, we refer to Charles's law, which states that at a constant pressure, the volume of a gas is directly proportional to its temperature in Kelvin. Based on this principle, to find the temperature at which a balloon will expand to a specific volume, you can use the formula:

V1/T1 = V2/T2, where:

V1 is the initial volume

T1 is the initial temperature

V2 is the final volume

T2 is the final temperature we need to find

Given that the initial volume (V1) of the gas is 3.50 L and the initial temperature (T1) is 300.0 K, and the final volume (V2) is 8.50 L, we can calculate the final temperature as follows:

T2 = (V2 * T1) / V1
T2 = (8.50 L * 300.0 K) / 3.50 L
T2 = 730 K

Therefore, the temperature at which the balloon will expand to 8.50 L is 730 K.

Answer 2

At volume 8.5 L, the temperature will be 728.57 K

Step-by-step explanation:

Given:

Volume, V₁ = 3.5L

Temperature, T₁ = 300K

Volume, V₂ = 8.5L

Temperature, T₂ = ?

According to Charle's law:

`(V_1)/(T_1) = (V_2)/(T_2)`

Substituting the value we get:

`(3.5)/(300) = (8.5)/(T_2) \\\\T_2 = (8.5 X 300)/(3.5)\\ \\T_2 = 728.57 K`

Therefore at volume 8.5 L, the temperature will be 728.57 K