Question

12.8 L of oxygen gas contains 0.0498 moles. At constant temperature and pressure, what volume does 0.0136 moles of the gas fill?

Answer 1

V₂ = 3.49 L

Step-by-step explanation:

Given data:

Initial volume of oxygen = 12.8 L

Number of moles = 0.0498 mol

Final volume = ?

Final number of moles = 0.0136 mol

Solution:

According to Avogadro law the number of moles of gas and volume are directly related to each other at constant temperature and pressure.

V₁/n₁ = V₂/n₂

Now we will put the values in formula.

12.8 L /0.0498 mol = V₂/ 0.0136 mol

V₂ = 12.8 L× 0.0136 mol/0.0498 mol

V₂ = 0.174 L.mol/0.0498 mol

V₂ = 3.49 L