Question

1. The gas in a used aerosol can is at a pressure 103 kPa at 25°C. If the can

is thrown into a fire, what will the pressure be when the temperature reaches
919°C?

Answer 1

412 kPa will the pressure be when the temperature reaches to 919°C.

Step-by-step explanation:

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

`(P_1)/(T_1)=(P_2)/(T_2)`

where,

`P_1\text{ and }T_1` are the initial pressure and temperature of the gas in a used aerosol can.

`P_2\text{ and }T_2` are the final pressure and temperature of the gas in a used aerosol can.

We are given:

`P_1=103 kPa\\T_1=25^oC=25+273K=298 K\\P_2=?\\T_2=919^oC=919+273 K=1,192 K`

Putting values in above equation, we get:

`(103 kPa)/(298 K)=(P_2)/(1,192 K)\\\\P_2=412 kPa`

412 kPa will the pressure be when the temperature reaches to 919°C.