Question

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1) The expression of concentration that provides the moles of solute per kilograms of solvent is _______.
2) If you place 5 moles of sodium chloride and 4 moles of sucrose into 11 moles of water, the _______ of sodium chloride would be 0.25.
3) A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the _______ is water.
4) A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the _______ is sodium chloride.
5) A way to express concentration that provides the moles of solute per liter of solution is _______.

a) molarity b) pH c) solvent d) solute e) morality f) mole fraction

Answer 1

Step-by-step explanation:

1) The expression of concentration that provides the moles of solute per kilograms of solvent is molality.

`molality=\frac{\text{Moles of solute}}{\text{Mass of solvent in kg}}`

2) If you place 5 moles of sodium chloride and 4 moles of sucrose into 11 moles of water, the mole fraction of sodium chloride would be 0.25.

Mole fraction is the fraction of moles of i-th component to the sum of all moles of components.

`\chi_i=(n_i)/(n_1+n_2...n_i)`

3) A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the solvent is water.

Solution made up two components that is solute and solvent. Amount of solvent is more than amount of solute.

4) A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the solute is sodium chloride.

5) A way to express concentration that provides the moles of solute per liter of solution is molarity .

`molarity=\frac{\text{Moles of solute}}{\text{Volume of solution in L}}`