Question

A 3.6-volt battery is used to operate a cell phone for an hour. If the cell phone draws a current of 0.018 Amperes during that time, what is the energy lost by the battery?

Answer 1

the energy lost by the battery is 233.28Joules

Step-by-step explanation:

Energy = Power × Time

We know that the power is given by :

`P=V * I`

Power = Current (I)×potential difference (V)

Energy lost = current × potential difference × time

`E = I * V * t`

Given that

current, I = 0.018Amperes,

Potential diff ,V = 3.6Volts

timr, t = 1hour = 1×60×60 = 3600seconds

Energy lost. = 0.018×3.6×3600

= 233.28Joules

Hence, the energy lost by the battery is 233.28Joules

Answer 2

233.28Joules

Step-by-step explanation:

Energy lost by the battery is expressed as

Energy = Power × Time

Since Power user up = Current (I)×potential difference (V)

Energy lost = current × potential difference × time

Energy used up = IVt

Given the following parameters

I = 0.018Amperes, V = 3.6Volts t = 1hour = 1×60×60 = 3600seconds

Energy lost. = 0.018×3.6×3600

Energy lost by the battery = 233.28Joules