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Steam enters a horizontal pipe operating at steady state with a specific enthalpy of 3000 kJ/kg and a mass flow rate of 0.5 kg/s. At the exit, the specific enthalpy is 1700 kJ/kg. If there is no significant change in kinetic energy from inlet to exit, the rate of heat transfer between the pipe and its surroundings is:____________

User Tmikeschu
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1 Answer

3 votes

Answer:

-650 KW

Step-by-step explanation:

We are given that

Initial specific enthalpy=
H_0=3000 kJ/kg

Exit specific enthalpy=
H_f=1700KJ/kg

Mass flow rate,
M_r=0.5 kg/s

We have to find the rate of heat transfer between the pipe and its surroundings.

Change in specific enthalpy=
\Delta H=H_f-H_0=1700-3000=-1300KJ/kg

Heat transfer rate=
\Delta H\cdot M_r

Heat transfer rate=
(-1300)* 0.5

Heat transfer rate=-650 KW

User Francesse
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