Question

(PLEASE ANSWER THESE 3 QUESTIONS FOR 50 POINTS)

Evaluate.
x+1/3

when x = -2.5

Question 1 options:

0.5


1.167


-1


-0.5

---------------------
Question 2

1/2(4 − 6y + 8)
Question 2 options:

6-3y


2 − 6y + 8

3y


2-3y
-------------------------------------------------
Question 3
Use distributive property to simplify:
3(x + 2)

Question 4 options:

3x + 6


3x + 2


6x


3/2

Answer 1

answers

question 1 = -0.5

question 2 = 6 - 3y

question 3 = 3x + 6

question 1

to evaluate (x + 1)/3 when x = -2.5, plug the value of x into the equation

(x + 1)/3

= (-2.5 + 1)/3

= (-1.5)/3

= -0.5

question 2

to solve this, distribute the 1/2 through the parentheses

(1/2) * (4 − 6y + 8)

= (1/2 * 4) + (1/2 * -6y) + (1/2 * 8)

= 2 + (-3y) + 4

= 6 - 3y

question 3

to solve this, distribute the 3 through the parentheses

3(x + 2)

= (3 * x) + (3 * 2)

= 3x + 6

note - i tried to plug -2.5 into x + (1/3) for question 1, but the answer wasn't among the solutions, so i assumed the equation was (x+1)/3 instead since its answer was among the solutions

Answer 2

`question \: \: \: 01 \\ x + (1)/(3) \\ x = - 2.5 \\ \\ - 2.5 + (1)/(3) \\ ( - 7.5)/(3) + (1)/(3) \\ = ( - 6.5)/(3) = 2.167`

Answer for the first question is not there. so,answer is 2.167

`question \: \: \: 02 \\ (1)/(2) (4 - 6y + 8) \\ = 2 - 3y + 4`

=6-3y

`question \: \: \: 03 \\ 3(x + 2) \\ 3x + 6`