Question

The graph of g is shown. Let f(x)=
`\int\limits^x__-2 \,`g(t)dt. What is f(1)?

Answer 1

Answer:
`-(9\pi )/(4)` or -7.0685. PLease rate if you found it helpful.

Answer 2

-7.07 (3 sf)

Explanation:

Integral gives the area between the curve and the axis

Region from x = -2 to x = 1 forms a quadrant with radius 3 units

Area = ¼ × 3.14 × 3²

= 7.065

Since the region is below the x-axis:

Integral value is -7.065