Question

A car battery has a rating of 250 ampere-hours. This rating is one indication of the total charge that the battery can provide to a circuit before failing. (a) What is the total charge (in coulombs) that this battery can provide? (b) Determine the maximum current that the battery can provide for 37 minutes.

Answer 1

Total charge provided by the battery could be 900000 C.

Maximum current provided by the battery for 37 minutes could be 405.405 A

Step-by-step explanation:

Rating= 250 A-h

a. Total charge:

`Rating=Q/t\\Q=Rating.t\\`

Suppose t=1h

`Q=250 A(1h)\\Q=250 A(3600 sec)\\Q= 900000 A.sec`

We konw that
`Ampere=(Coulomb)/(sec)`, replacing:

`Q=900000((Coulomb)/(sec))(sec)\\Q=900000 Coulomb`

Total charge provided by the battery could be 900000 C.

b. Maximum current for 37 minutes

`I=(Q)/(t) \\I=(900000 C)/(37*60 sec)\\I=405.405 A`

Maximum current provided by the battery for 37 minutes could be 405.405 A