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For the general chemical equation 2A + 3B + 4C+D, how many moles of A are required to produce 18.4 mol of C?

a. 9.2 mol
b. 13.8 mol
c. 36.8 mol
d. 73.6 mol

2 Answers

2 votes

Final answer:

For the chemical equation 2A + 3B + 4C → D, 9.2 moles of A are required to produce 18.4 mol of C, as determined by the stoichiometric relationship between reactants and products. So the correct option is a.

Step-by-step explanation:

For the general chemical equation given, which we can restate as 2A + 3B + 4C → D, we want to determine how many moles of the reactant A are required to produce 18.4 mol of the product C.

According to the stoichiometry of the equation, 4 moles of C are produced for every 2 moles of A consumed. This means that the ratio of A to C is 1:2. Therefore, to calculate the number of moles of A needed to produce 18.4 moles of C, we set up a simple proportion:

2 moles of A / 4 moles of C = x moles of A / 18.4 moles of C

By cross-multiplying to solve for x, we get:

x = (2 moles of A × 18.4 moles of C) / 4 moles of C

x = 9.2 moles of A

Therefore, 9.2 moles of A are required to produce 18.4 moles of C.

The correct answer is a. 9.2 mol.

User Daniel Marx
by
8.0k points
1 vote
a. 9.2 mol because the mole ration of A to C is 2:4 so the answer is half
User Yasin Hassanien
by
8.0k points

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