Answer:
Explanation:
Completing square:
3 + x = x² + 3x
x² + 3x = x + 3
Step 1: Subtract 'x' from both sides
x² + 3x - x = 3
x² + 2x = 3
Step 2: Divide the coefficeint of x by 2 and square the result
2 ÷ 2 = 1
1² = 1
Step 3: Now add 1 to both the sides
x² + 2x + 1 = 3 + 1
x² + 2x + 1 = 4
The LHS of the equation is in the form a² + 2ab + b² = (a +b)²
(x + 1)² = 2²
Take square root,
x + 1 = ± 2
x + 1 = 2 ;x + 1 = -2
x = 2 - 1 ; x = - 2-1
x = 1 ; x = -3
Solution: x = 1,-3