Answer:
T₂ = 687.6 K
Step-by-step explanation:
Given data:
Initial pressure = 108 Kpa = 108/101 = 1.06588 atm
Initial temperature = 20°C = 20+273.15 = 293.15 k
Final temperature = ?
Final pressure = 2.50 atm
Solution:
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
1.06588 atm / 293.15 K = 2.5 atm/T₂
T₂ = 2.5 atm ×293.15 K / 1.06588 atm
T₂ = 732.875 atm. K /1.06588 atm
T₂ = 687.6 K