Answer:
![\sf{-3\displaystyle(1)/(2) }](https://img.qammunity.org/2023/formulas/mathematics/college/nowkrh8dsdlrigdjjbkz1u6g9bfk58suf0.png)
Solution:
- First, we need to flop the second fraction over.
- Then, we need to multiply the first fraction times the second fraction.
- In order to multiply fractions, we need to multiply the numerator of the first fraction times the numerator of the second fraction:
![\displaystyle(1)/(2) *-(7)/(1)](https://img.qammunity.org/2023/formulas/mathematics/college/g797fwyqa4v8ycceeiivpkpue6rwqxpy5j.png)
![-\displaystyle(7)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/uf9x3yhrk6ik6yby4uxu5xu3pij56mykd4.png)
- Now, let's convert the improper fraction into a mixed number.
- First, how many times does 2 go into 7? (evenly)
- The answer is 3.
- Now, multiply 3 times 2. We get 6.
- Subtract 7-6. We get 1.
- The denominator stays the same.
- Therefore, the answer is
![-3\displaystyle(1)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/lo7kl0sqzeqye7wl78c3vhd00231liqmrg.png)
Hope it helps.
Do comment if you have any query.