Question

Uestion 1

How many sulfur atoms are present in 26.1 grams of Al253?
Answer should have 3 significant figures adn in scientific notation​

Answer 1

`3.14 * 10^(23) \text{ S atoms}`

Step-by-step explanation:

1. Calculate the moles of Al₂S₃

`\text{Moles of Al$_(2)$S}_(3) = \text{26.1 g} * \frac{\text{1 mol}}{\text{150.16 g}} = \text{0.1738 mol Al$_(2)$S}_(3)`

2. Calculate the moles of S atoms

`\text{Moles of S atoms} = \text{0.1738 mol Al$_(2)$S}_(3) * \frac{\text{3 mol S atoms }}{\text{1 mol Al$_(2)$S}_(3)} = \text{0.5214 mol S atoms}`

3. Calculate the number of S atoms

`\text{No. of S atoms} = \text{0.5214 mol S atoms} * \frac{6.022 * 10^(23) \text{ S atoms}}{\text{1 mol S atoms}} = \mathbf{3.14 * 10^(23)} \textbf{ S atoms}`