Question

To prepare 1.00 L of 14g BaCl2, what Molarity would it be?​

Answer 1

0.067 M

Step-by-step explanation:

Given data:

Volume of solution = 1.00 L

Mass of BaCl₂ = 14 g

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Now we will calculate the number of moles first.

Number of moles = mass/ molar mass

Number of moles = 14 g/ 208.23 g/mol

Number of moles = 0.067 mol

Now we will calculate the molarity.

Molarity = 0.067 mol / 1.00 L

Molarity = 0.067 M ( mol/L=M)