Question

2000 fun size snickers have dimensions 2 inches by 1/2 in by 1 in. Today a fun size snickers has dimensions 1 1/2 in by 1/4 in by 1/2 in. What is the percent decrease in the volume of the snickers

Answer 1

81.25%

Explanation:

Given:

A fun size snickers have earlier dimensions 2 inches by 1/2 inches by 1 inches.

Today a fun size snickers has dimensions 1 1/2 inches by 1/4 inches by 1/2 inches.

Question asked:

What is the percent decrease in the volume of the snickers ?

Solution:

Old dimensions of snooker = 2 inches by
`(1)/(2)` inches by 1 inches

Volume of old snooker =
`length* breadth * height`

`=2*(1)/(2) *1=(2)/(2) =1\ cubic \ inches`

New dimensions of snooker =
`1(1)/(2)` inches by
`(1)/(4)` inches by
`(1)/(2)`

Volume of new snooker =
`length* breadth\ height`

`=1(1)/(2)*(1)/(4) *(1)/(2) \\ \\ =(3)/(2) *(1)/(4) *(1)/(2)=(3)/(16) \ cubic\ inches`

`Percent\ changed=(New\ volume-old\ volume)/(old\ volume) *100`

`=(3)/(16) -1/1*100\\ \\ =(3-16)/(16) *100\\ \\ =(-13)/(16) *100\\ \\ =(-1300)/(16) \\ \\ =-81.25\%`

Here negative sign shows that new volume is decreased.

Therefore, 81.25% decrease in the volume of the snickers.