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What is the solution to -4(8-3x) >_6x-8
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What is the solution to -4(8-3x) >_6x-8

User NanoWizard
by
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1 Answer

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Answer:

x ≥4

Explanation:

-4(8-3x) ≥6x-8

Distribute

-32+12x ≥6x-8

Subtract 6x from each side

-32+12x-6x ≥6x-6x-8

-32+6x ≥-8

Add 32 from each side

-32+32 +6x ≥-8+32

6x ≥ 24

Divide each side by 6

6x/6 ≥24/6

x ≥4

User Big Dogg
by
4.3k points
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