Question

Givin sin0= 12/13, find sec(0)

A. Sec(0)= 13/12

B. Sec(0)= 5/13

C. Sec(0)= 5/12

D. Sec(0)= 13/5

Answer 1

D. sec(a) = 13/5

Explanation:

if sin(a) = 12/13, then cos (a) = 5/13, because of 5-12-13 triangles

sec(a) = 1/cos(a)

1/(5/13) = 13/5

sec(a) = 13/5