Question

Kanye, Taylor's lab partner decided to perform a standard plate count from a sample of E. coli. Understanding that the plates should have 30 - 300 colonies, Kanye decide to aim for exactly 100 colonies.

If the original sample contained 1 x 10^8 CFU/ml, what is the total dilution that would yield 100 colonies?

Answer 1

Total dilution is 10^5 that would yield 100 colonies.

Step-by-step explanation:

1 x 10^8 cfu/mL * 1/x = 100 colonies

x= 10^6 cfu/ml

So,

1*106cfu/ml *0.1 ml plated

=10^5