Answer:
Explanation:
Assuming the image is the shown below, we can use the following formula to find the length of arc
:
![L_(arc)=2 \pi R ((\theta)/(360 \°))](https://img.qammunity.org/2021/formulas/mathematics/middle-school/n7r7ie3dbczxy1mlozvh7hm2bi6vuhnc5l.png)
Where
is the angle in the arc and
is the radius of the circle.
Since we are not given the value of
, we will only work with this.
For
:
![L_(arc-GIF)=2 \pi R ((71\°)/(360 \°))](https://img.qammunity.org/2021/formulas/mathematics/middle-school/xn0yiqcip9d4v00tfn22fasa6h4xn7v7ge.png)
![L_(arc-GIF)=1.239 R](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ijcb4819j9l8pjpmz5omouiyhq19qtolyr.png)
For
:
We firstly need to find the value of this angle, taking into account the whole circumference is
:
![360 \°=71 \°+53 \°+HET+20 \°](https://img.qammunity.org/2021/formulas/mathematics/middle-school/8lsgvyashcwvsb5iaicegy3kc0omunylkz.png)
Finding
:
![HET=216 \°](https://img.qammunity.org/2021/formulas/mathematics/middle-school/p1kiitxrkr3c2agb4sn7whdi6ph514bysn.png)
Now, let's calculate the length of arc:
![L_(arc-HET)=2 \pi R ((216\°)/(360 \°))](https://img.qammunity.org/2021/formulas/mathematics/middle-school/bfgy5nvt47m6qwjti93z2tvrmfqrqta9ma.png)
![L_(arc-HET)=3.769 R](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4efum1jtiwofin9q7e2kix42weccpw9r8i.png)