Answer:
![arc\ WUX=120^o](https://img.qammunity.org/2021/formulas/mathematics/high-school/cozqfeimt9zm0ptdwxw3koo8c60kdytha0.png)
Explanation:
The complete question is:
In circle V, angle WXZ measures 30°. Line segments WV, XV, ZV, and YV are radii of circle V. Circle V is shown. Line segments W V, X V, Z V, and Y V are radii. Lines are drawn from point W to point X and from point Z to point Y to form secants. Point U is on the circle between points W and X. What is the measure of Arc W U X in circle V?
The picture of the question in the attached figure
step 1
Find the measure of angle XWV
we know that
The triangle VWX is an isosceles triangle, because has two equal sides (VX=VW)
we have
![m\angle WXZ=30^o\\m\angle WXV=m\angle WXZ](https://img.qammunity.org/2021/formulas/mathematics/middle-school/a8jyr2lxw7al4itmiaszd9gc61av9iany9.png)
so
![m\angle WXV=30^o](https://img.qammunity.org/2021/formulas/mathematics/high-school/v9dqr0vx6pcjnf36bu8l2s8980q0zxdlui.png)
Remember that an isosceles triangle has two equal interior angles
so
step 2
Find the measure of angle WVX
Remember that the sum of the interior angles in any triangle must be equal to 180 degrees
so
![m\angle\ WVX+m\angle XWV+m\angle WXV=180^o](https://img.qammunity.org/2021/formulas/mathematics/high-school/q03e98s6h85xdvoam3qh3a4ggfzpo48tvr.png)
substitute the given values
![m\angle WVX+30^o+30^o=180^o\\m\angle WVX=180^o-60^o=120^o](https://img.qammunity.org/2021/formulas/mathematics/middle-school/3cuobtq66uti0eaaiagdm74ae0ebzgczus.png)
step 3
Find the measure of arc WUX
we know that
----> by central angle
we have
![m\angle WVX=120^o](https://img.qammunity.org/2021/formulas/mathematics/high-school/8ils4yzfg55vrwu13f8tkf99aep88mhay1.png)
therefore
![arc\ WUX=120^o](https://img.qammunity.org/2021/formulas/mathematics/high-school/cozqfeimt9zm0ptdwxw3koo8c60kdytha0.png)