Question

The acceleration of a baseball pitcher's hand as he delivers a pitch is extreme. For a professional player, this acceleration phase lasts only 50 ms, during which the ball's speed increases from 0 to about 90 mph, or 40 m/s.

What is the force of the pitcher's hand on the 0.145 kg ball during this acceleration phase? Express your answer with the appropriate units.

Answer 1

116 N.

Step-by-step explanation:

Given,

mass of the ball, m = 0.145 Kg

initial speed = 0 m/s

Final speed = 40 m/s

time = 50 ms = 0.05 s

Force is equal to change in momentum per unit time

`F = (m\Delta v)/(\Delta t)`

`F = (0.145(40-0))/(0.05)`

F = 116 N

Force of the pitcher hand on the ball is equal to 116 N.