Answer:
172 Hz
Step-by-step explanation:
We are given that
Distance between speaker A and B=2 m
Distance between speaker B and point Q=1 m
We have to find the lowest frequency for which constructive interference occurs at point Q.
Where n=Integer
When frequency is minimum then wavelength is maximum
when n=1
![\lambda_(max)=2](https://img.qammunity.org/2021/formulas/physics/college/3nzoeq5s1canidkwd1z31un5dotzdb6mb3.png)
![\\u=(v)/(\lambda_(max))](https://img.qammunity.org/2021/formulas/physics/college/85d1ctq4b085hyo4jpqq03mc7s7ttkekok.png)
Speed of sound,v=344 m/s
![\\u=(344)/(2)=172 Hz](https://img.qammunity.org/2021/formulas/physics/college/y7u8njub9sc2dmnc7n6e5n4s1bgy4hqfay.png)