Answer : The molar concentration of
in the solution is, 4.27 M
Explanation : Given,
Mass of
= 25.0 g
Volume of solution = 100.0 mL
Molar mass of
= 58.5 g/mole
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
![\text{Molarity}=\frac{\text{Mass of }NaCl* 1000}{\text{Molar mass of }NaCl* \text{Volume of solution (in mL)}}](https://img.qammunity.org/2021/formulas/chemistry/college/re968z5srxard1qufgsbaqbqdn0v3yt9fm.png)
Now put all the given values in this formula, we get:
![\text{Molarity}=(25.0g* 1000)/(58.5g/mole* 100.0mL)=4.27mole/L=4.27M](https://img.qammunity.org/2021/formulas/chemistry/college/nrneeci2dyuu7cpvo9129rqmirvu8msaga.png)
Therefore, the molar concentration of
in the solution is, 4.27 M