Answer:
f = 4.85 Hz
Step-by-step explanation:
This question is an example of the Doppler's effect
We are given that ;
The source velocity; v_s = 10 m/s
The apparent frequency f'= 5 Hz
We will also need the speed of sound in air and it has a constant value of 340 m/s. Thus, v = 340 m/s
Now, the true frequency is given by the formula;
f = [(v - v_s)/v]•f'
Where;
v is speed of sound in air
v_s is speed of source
f' is apparent frequency
Thus, plugging in the relevant values, we have;
f = [(340 - 10)/340]•5
f = (330/340)•5
f = 4.85 Hz