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For a particular pipe in a pipe-organ, it has been determined that the frequencies 296 Hz and 370 Hz are two adjacent natural frequencies. Using 343 m/s as the speed of sound in air, determine the following. (a) fundamental frequency for this pipe ______ Hz

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Answer:

fundamental frequency of pipe will be equal to 74 Hz

Step-by-step explanation:

We have given for a particular organ pipe two adjacent frequency are 296 Hz and 370 Hz

Speed of the sound in air is 343 m/sec

We have to find the fundamental frequency for the pipe

Fundamental frequency will be equal to difference of the two adjacent frequency

So fundamental frequency = 370 - 296 = 74 Hz

So fundamental frequency of pipe will be equal to 74 Hz

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