Question

The interior dimensions of Mr. Tran's pet fish Mino fish tank are 4 feet long, 3 feet wide, and 2 feet high. The water level in the tank is 1 feet high. All the water in this tank is poured (with Mino) into an empty second tank. If the interior dimensions of the second tank are 3 feet long, 2 feet wide, and 4 feet high, what is the height of the water in the second tank?

Answer 1

2 feet

Explanation:

The question demands for us to find the height of water poured into the second tank from the first one.

Both tanks share the same volume but have different dimensions.

Tank A has the following dimensions:

Length is 4 feet long

Width is 3 feet wide

And also 2 feet high

Tank B has the dimensions below

Length is 3 feet long

Width is 2 feet wide

And has a height of 4 feet.

Let's now assume to not knowing the heights of both tanks

----- Tank A occupies a certain amount of water at 1 feet high with length 4 feet and width 3 feet,the area of this rectangular tank is 12 feet square.

----- Tank B occupies the same amount of water as Tank A and with a height unknown, but with a shared volume as that as Tank A and dimensions length and width as 3 and 2 feet respectively, the area of this rectangular tank will be 6 square feet which is twice as less as that of Tank A.

Height of water of Tank B is equal to 12/6 = 2 feet

Answer 2

The height of water in the second tank is 2ft

Explanation:

In this question, we are asked to calculate the height of water in a second tank if the content of a first tank is poured into the second tank.

The plot twist to answering this question is that we need to note the volume of water in the first tank. Although the first tank has dimensions of 2ft by 3ft by 2ft height, the water in the tank only rose to a height of 1 feet.

Hence, to calculate the volume of the water in the first tank, the width and the length of the tank still remain the same, the only difference here is that we work with a height of 1 feet since the Water is not full.

Mathematically, the volume of water present in the tank will be;

V = l * b * h

V = 4 * 3 * 1 = 12 cubic feet

Now, this content is emptied into a second tank. Since the volume of water here is the same; this means;

12 cubic feet = 3 * 2 * h

We ignore the 4ft height as it is just the height of the tank and not the height of the water in the tank

6h = 12 cubic feet

h = 12/6 = 2 ft