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A 1.45 kg falcon catches a 0.515 kg dove from behind in midair. What is their velocity after impact if the falcon's velocity is initially 26.5 m/s and the dove's velocity is 4.95 m/s in the same direction?

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Answer:

Their velocity after the impact is 20.85 m/s.

Step-by-step explanation:

Given that,

Mass of falcon,
m_1=1.45\ kg

Mass of dove,
m_2=0.515\ kg

Initial speed of the falcon,
u_1=26.5\ m/s

Initial speed of the dove,
u_2=4.95\ m/s

We need to find the final velocity after the impact. When the falcon catches the dove, it will becomes the case of inelastic collision. The conservation of momentum will be :


m_1u_1+m_2u_2=(m_1+m_2)V\\\\V=(m_1u_1+m_2u_2)/((m_1+m_2))\\\\V=(1.45* 26.5+0.515* 4.95)/((1.45+0.515))\\\\V=20.85\ m/s

So, their velocity after the impact is 20.85 m/s.

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