Question

3. Calculate the mass of oxygen produced from the decomposition of 75.0 g of potassium chlorate.

2KClO3(s)  2KCl(s) + 3O2(g)

Answer 1

29.3 grams

Step-by-step explanation:

2KClO3 - > 2 KCl + 3O2

Moles of KClO3=75. g/123 g/mol=0.610 mol

Moles of O2 =0.610 mol* 3/2=0.915 mol

Mass of oxygen = 0.915 mol x 32 g/mol=29.3 g