Question

A baseball team has three positions open: first base,

third base, and right field. Six players are trying out
for these positions. In how many different ways can
these positions be filled?

Answer 1

Number of different ways of placing the players are 120

Step-by-step explanation:

Given:

Three positions in baseball team are there = __ __ __

Number of players trying = 6

Number of ways in which these positions can be filled = ?

6 __ __ in first position, all 6 players have the chances to be positioned

6 5 __ In second position, 5 players have the chances to be positioned

6 5 4 In third position, 4 players have the chances to be positioned.

Therefore, different ways in which the players can be positioned = 6 X 5 X 4

= 120