How many moles of water vapors are formed when 10L of butane gas is burned in oxygen at STP?

asked Nov 18, 2021 142k views

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Answer:

10L / 22.4mol/L = 0.446mol

Step-by-step explanation:

each mole of butane yields 5 moles of water

a mole of gas at stp is 22.4 L

10/22.4 * 5

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