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How many moles of water vapors are formed when 10L of butane gas is burned in oxygen at STP?​
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5 votes
How many moles of water vapors are formed when 10L of butane gas is burned in oxygen at STP?​

User Minchaej
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1 Answer

4 votes

Answer:

10L / 22.4mol/L = 0.446mol

Step-by-step explanation:

each mole of butane yields 5 moles of water

a mole of gas at stp is 22.4 L

10/22.4 * 5

User Max Romanovsky
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