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Assume the random variable x is normally distributed with mean u = 90 and standard deviation o=5. Find the indicated probability.

P(X<80) =
(Round to four decimal places as needed.)

User MichM
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1 Answer

4 votes

Given:

Let the random variable x is normally distributed with mean
\mu=90 and
\sigma=5

We need to determine the probability of
P(X<80)

Probability of
P(X<80):

The formula to determine the value of
P(X<80) is given by


Z=(X-\mu)/(\sigma)

Thus, we have;


P(X<80)=P(Z<(80-90)/(5))

Simplifying, we get;


P(X<80)=P(Z<(-10)/(5))


P(X<80)=P(Z<-2)

Using the normal distribution table, the value of -2 is given by 0.0228


P(X<80)=0.0228

Thus, the value of
P(X<80) is 0.0228

User Salexch
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