Question

326L

A cylinder with a movable piston contains 0.500 mol of helium, He, at
som temperature. More helium was added to the cylinder and the volume
as adjusted so that the gas pressure remained the same. How many
holes of helium were added to the cylinder if the volume was changed
rom 2.00 L to 2.70 L? (The temperature was held constant.) *
"our answer
!
This is a required question
B. How many grams of Helium would be added in question #2? *

Answer 1

Final number of moles = 0.675 mol

Mass = 2.7 g

Step-by-step explanation:

Given data:

Initial volume of gas = 2.00 L

Final volume of gas = 2.70 L

Initial number of moles = 0.500 mol

Final number of moles = ?

Solution:

Formula:

V₁/n₁ = V₂/n₂

V₁ = Initial volume

n₁ = Initial number of moles

V₂ = Final volume of gas

n₂ = Final number of moles

Now we will put the values in formula.

2.00 L /0.500 mol = 2.70 L / n₂

n₂ = 2.70 L× 0.500 mol /2.00 L

n₂ = 1.35 L.mol / 2.00 L

n₂ = 0.675 mol

B)

Grams of helium added = ?

Solution:

Mass = number of moles × molar mass

Mass = 0.675 mol× 4 g/mol

Mass = 2.7 g